X^2+16x=960

Solution for X^2+16x=960 equation:

X^2+16X=960

We move all terms to the left:

X^2+16X-(960)=0

a = 1; b = 16; c = -960;
Δ = b2-4ac
Δ = 162-4·1·(-960)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-64}{2*1}=\frac{-80}{2}
=-40
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+64}{2*1}=\frac{48}{2}
=24
$